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Partial derivatives review

  1. Aug 31, 2006 #1
    Ok i got this problem...
    T(x,y,z,t)= -2xy^2+e^(-3z)cos(5x-.75t)
    taking the partial derivative with respect to x first, so i break the problem apart with the left and right sign of the addition side

    so i get...
    -2y^2 for the left side and then am stubling on the right side, im think just chain rule since e^(-3z) is constant right? so I get -sin(5x-.75t)5 from the right side.

    any help
     
  2. jcsd
  3. Aug 31, 2006 #2

    quasar987

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    So the final answer for [itex]\partial T/\partial x[/itex] is what according to you?
     
  4. Aug 31, 2006 #3
    its -2y^2-e^(-3z)*sin(5x-.75t)5 I THINK, butttt... i have a voyage 200 near me and when i check it, its giving me a error and I don't trust myself enough to think its right...
     
    Last edited: Aug 31, 2006
  5. Aug 31, 2006 #4

    quasar987

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    That's the correct answer. What's a voyage 200?
     
  6. Aug 31, 2006 #5
    its a TI calculator that does alot.
     
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