Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Partial fraction decomposition of the cosine

  1. Apr 23, 2008 #1


    User Avatar

    1. The problem statement, all variables and given/known data

    with the "standard" method and with the method of the partial fraction decomposition of the cosine.

    2. Relevant equations

    [tex]\pi\cot\pi z=\frac{1}{z}+\sum_{k=1}^{\infty}\frac{2z}{z^{2}-k^{2}}[/tex]

    3. The attempt at a solution

    The "standard" method wasn't a problem just partial fraction decomposition and some index-shifting. the result is 3/4.
    However, when it comes to the cosine function my problem is that I can't plug integers (i.e. 1) in the function because it isn't defined there. Thus, i tried rewriting the term; however, the only rewriting of the term that leads to a result is to do the usual partial fraction decomposition which sort of defeats the purpose.
  2. jcsd
  3. Apr 23, 2008 #2


    User Avatar
    Science Advisor

    I have no idea what you mean by the "partial fraction decomposition of the cosine".
  4. Apr 23, 2008 #3


    User Avatar

    Well it should actually read "partial fraction decomposition of the cotangent" (thus the formula)

    The idea is to write the cotangent as a infinite series of partial fractions (because there are infinite many zero's of the denominator of cos(x)/sin(x)). If you do this you arive at the formula given above.
    Last edited: Apr 23, 2008
  5. Apr 23, 2008 #4

    Gib Z

    User Avatar
    Homework Helper

    Of course it won't work for integers. When you take the k=z term of the sum, what happens?
  6. Apr 23, 2008 #5


    User Avatar

    yeah I know that it doens't work for integers so I have to rewrite it somehow so that I can calculate the given series with the formula (as is stated in the exercise). The problem is I don't really know how to do that.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook