Partial Sums for Series: Solving Using Partial Fractions

gkamal
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Homework Statement


t5672v.jpg
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Homework Equations



an= bn - bn+1 which is already in the problem

The Attempt at a Solution


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i did partial fractions but then i got stuck at

16/12 [4n-5] - 16/12 [4n+7] that part about bn confuses me please someone explain in detail
 
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gkamal said:

Homework Statement


t5672v.jpg
[/B]

Homework Equations



an= bn - bn+1 which is already in the problem

The Attempt at a Solution


[/B]
i did partial fractions but then i got stuck at

16/12 [4n-5] - 16/12 [4n+7] that part about bn confuses me please someone explain in detail
Where's the equation you're working with?
Starting from ##\frac{16}{16n^2 + 8n - 35} = \frac{A}{4n - 5} + \frac{B}{4n + 7}##, multiply both sides by ##16n^2 + 8n - 35## to clear out all of the denominators. Then solve for the constants A and B.
 
i did and i get 16/12 for A and - 16/12 for B as i indicated above the problem is what is the next step
 
I think there's a typo in the problem. It should say ##a_n = b_n - b_{n+3}##.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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