Partice Kinetics Question - HELP

  • Thread starter Thread starter Cam169677
  • Start date Start date
  • Tags Tags
    Kinetics
AI Thread Summary
The discussion centers on calculating the acceleration of a block moving down a slope, factoring in a kinetic coefficient of friction of 0.4. Participants express confusion about determining the normal reaction force due to the pulley angle and how to incorporate a 47N force in their calculations. Clarifications are sought regarding the angles involved, specifically whether the angle between the upper rope and the slope is 31º and the orientation of the lower rope. Suggestions include using Newton's second law to analyze forces and breaking down the components of the forces acting on the block. Overall, the thread emphasizes the need for clear problem-solving steps and collaboration to resolve the physics questions presented.
Cam169677
Messages
1
Reaction score
0

Homework Statement


As shown in the attachment.
At the instant shown the block is moving down the slope. What is the acceleration of the block up the slope if the kinetic coefficient of friction is 0.4?


The Attempt at a Solution



I'm having problems with two things here, the calculation of the normal reaction on the block as i don't know what to do about the angle of the line on the pulley and its resultant force...
This leads to my second problem when summing the total force in the x-direction i still don't know what to do with the 47N force...

Generally i need help!
 

Attachments

  • untitled1.JPG
    untitled1.JPG
    9.5 KB · Views: 430
Physics news on Phys.org
Welcome to PF!

Hi Cam169677! Welcome to PF! :smile:

(is 31º the angle between the upper rope and the slope, and is the lower rope suppposed to be parallel to the slope? :confused:)
Cam169677 said:
I'm having problems with two things here, the calculation of the normal reaction on the block as i don't know what to do about the angle of the line on the pulley and its resultant force...

There's no acceleration in the normal direction, so just use good ol' Newton's second law in that direction … ∑F = 0. :wink:
This leads to my second problem when summing the total force in the x-direction i still don't know what to do with the 47N force...

what's the x-direction?

the obvious direction to use is the direction of the slope …

then the component of the 47N in that direction is 47(cos31º)N
 
I'm also having trouble with this.

"is 31º the angle between the upper rope and the slope, and is the lower rope suppposed to be parallel to the slope?"

That's what i want to find out as well hmm
 
Welcome to PF!

Hi PcKSnipE! Welcome to PF! :smile:
PcKSnipE said:
"is 31º the angle between the upper rope and the slope, and is the lower rope suppposed to be parallel to the slope?"

That's what i want to find out as well hmm

I assume it is.
 
Alright i worked it out, the tricky bit has to do with the pulley.

The total force of the pullet in the X plane is T + TcosA
The force in the normal direction (which affects friction) is mgcosA - TsinA

Gl
 
i still don't get wat to do here guys i have a similar question but using the following example can u tell me step by step wat to do and a answer as well
Thanx much appreciated
 
welcome to pf!

hi jalwa! welcome to pf! :wink:

better start a new thread …

make sure to show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
Back
Top