Particle in a box, some clarification please

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the energy of an n state can be given by:

E = (nh)^2 / 8mL^2

is this a representation of the Kinetic energy of the particle? i thought it was but this question has got me confused.

it asks for the Energy of the n=1 state, which I've done. then it asks what quantum number, n would be needed if the Kinetic Energy was 0.025eV.

i rearranged the above eqn for n and put E= (0.025ev X 1.6x10^-19 ), but get something stupid as a result.

so, is E the energy of the state of the particle OR it's kinetic energy OR both?

Thanks in advance for any help.
 
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Hmm, the energy state is the total energy, but as you only have kinetic energy, it should be straight forward, as you've done.
 
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The potential in the case of particle in a box problem,is zero inside the box and greater than zero outside it.So inside the box,the total energy of the particle is equal to its kinetic energy.
 
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yes this is as i suspected, i get a stupidly high number for n and its not a whole number either! will recalculate.

thanks for the replies!
 
Well, getting a whole number for n is quite unrealistic, when you think about the numbers and decimals, you are using.

Also I don't think there are any limits for the quantum number for a particle in a box.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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