Throughout space there is a uniform electric field in the -y direction of strength E = 450 N/C. There is no gravity. At t = 0, a particle with mass m = 4 g and charge q = -19 µC is at the origin moving with a velocity v0 = 40 m/s at an angle θ = 25° above the x-axis.
(a) What is the magnitude of the force acting on this particle?
F = 0.00855N
(b) At t = 5.7 s, what are the x- and y-coordinates of the position of the particle?
x = 206.6381754m
y = ?
y = y0 + vy0*t + 0.5*ay*t2
vx = v*cos(25)
vy = v*sin(25)
a = m/F
The Attempt at a Solution
a = 0.004/0.00855 = 0.467836257
vy = 40*sin(25) = 16.90473047
y = 16.90473047*5.7 + 0.5*(-0.467836257)*5.7^2 = 88.75696368
Im not sure where I messed up here. Any thoughts?