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## Homework Statement

Throughout space there is a uniform electric field in the -y direction of strength E = 450 N/C. There is no gravity. At t = 0, a particle with mass m = 4 g and charge q = -19 µC is at the origin moving with a velocity v0 = 40 m/s at an angle θ = 25° above the x-axis.

(a) What is the magnitude of the force acting on this particle?

F = 0.00855N

(b) At t = 5.7 s, what are the x- and y-coordinates of the position of the particle?

x = 206.6381754m

y = ?

## Homework Equations

y = y

_{0}+ v

_{y0}*t + 0.5*a

_{y}*t

^{2}

v

_{x}= v*cos(25)

v

_{y}= v*sin(25)

a = m/F

## The Attempt at a Solution

a = 0.004/0.00855 = 0.467836257

v

_{y}= 40*sin(25) = 16.90473047

y = 16.90473047*5.7 + 0.5*(-0.467836257)*5.7^2 = 88.75696368

Im not sure where I messed up here. Any thoughts?

Thanks!