Pascal Law: Pressure Increase in Symmetrical Container

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Homework Help Overview

The discussion revolves around a problem involving Pascal's Law in the context of a symmetrical container filled with water and subjected to forces applied by pistons. Participants are exploring the implications of pressure changes within the fluid when additional forces are applied.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the definition of pressure and its application to the problem, particularly regarding the calculation of pressure when forces are applied from multiple sides. There is a debate about whether to consider the forces as a vector sum or as scalars.

Discussion Status

The discussion is active, with participants providing insights into the nature of pressure as an intensive variable and its independence from the size of the system. Some guidance has been offered regarding the scalar nature of pressure, but multiple interpretations of the problem are still being explored.

Contextual Notes

There appears to be confusion regarding the application of forces in a fluid versus a solid, as well as the implications of applying forces from all sides of the container. The original poster's understanding of pressure and its calculation is under scrutiny.

jonny23
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Homework Statement



a water filled symetrical container has four pistons , one on each side of area A to keep water in equilibrium

Now an additional force F is applied to all four pistons . then increase in pressure at the middle of container will be:

Homework Equations


pascal law: change is pressure is transmitted to whole fluid

The Attempt at a Solution


since F is applied from four sides so pressure should have been 4F/A but the solution says F/A
 

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What's the definition of pressure?
 
Perpendicular force per unit area..
 
Now apply that definition to the problem.
 
but the force is from all sides so either vector sum should be 0
or if add as scalar it should be 4F/A...
but the answer is only F/A
 
The force is being applied to a fluid, not a solid. What happens when you stand on a water balloon?
 
can you give a more detailed reply to this question...
 
jonny23 said:
Perpendicular force per unit area..
jonny23 said:
but the answer is only F/A
4F/4A is the same thing as F/A. If we're discussing pressure as a thermodynamic variable, it's what is called an intensive variable, independent of the size of a system. Mathematically, it's a scalar. Force has a direction, yes; force per unit area has no direction. Pressure times area has a direction. The scalar-vector conflict may be what's confusing you. Stick with it, and we'll sort it out for you.
 
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