Max Vehicle Weight for 19.3 atm Hydraulic Lift (23.8 cm Diameter)

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The maximum gauge pressure of 19.3 atm in a hydraulic lift translates to 1.96e6 N/m^2. To find the largest vehicle weight it can lift, the cross-sectional area of the output line, with a diameter of 23.8 cm, is calculated using the radius of 0.119 m. Multiplying the pressure by this area yields the lifting force in Newtons. To convert this force into mass, divide by the acceleration due to gravity (9.81 m/s^2). This method effectively determines the maximum vehicle weight the hydraulic lift can handle.
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im back again with another problem. The maximum gauge pressure in a hydraulic lift is 19.3 atm. What is the largest size vehicle ( kg) it can lift if the diameter of the output line is 23.8 cm?
What I did was convert 19.3 atm to 1.96e6 N/m^2, then I got density by using the formual P= rho x g x h, my result was a density of 8.40e5 kg/m^3. My goal was to determine the volume and then get mass using m= rho x V. Is this the right way to go about this problem?
 
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I don't see any reason to get that complicated. You already have the pressure in N/m^2 and you know the diameter of the output line is 23.8 cm so the radius is 11.9 cm= 0.119 m. You can calculate the cross section area of the output line which is the area to which the pressure is applied. Multiply the pressure in N/m^2 by the area in m^2 to get the force in N. Since the problem asks for the answer in kg, you will have to divide the force (weight that can be lifted) by 9.81 to get the mass.
 
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