# Path of a particle.

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1. Mar 31, 2016

### LoveBoy

1. The problem statement, all variables and given/known data

2. Relevant equations
Find the path of a particle.
What is the general or fundamental way to solve this type of questions ?

3. The attempt at a solution
I don't know where do i start.
I can't able to find a relation between these vectors.

2. Mar 31, 2016

### Staff: Mentor

Suppose for a moment that the initial velocity of the particle happened to be zero (the particle starts from rest). What type of path would you expect for a constant force being applied?

3. Mar 31, 2016

### PeroK

I've already given you the formulas for vector motion in another post. So, either you don't understand vectors or you don't understand motion in more than one dimension.

Can you draw a crude diagram of roughly what is going to happen to the particle?

Imagine you were running with the initial velocity and someone was pushing you in the direction of the force. Or, that someone is pushing you in the $\hat{i}$ direction and someone else is pushing you in the $\hat{j}$ direction. You need to find some way to relate these things to the real world.

But, then you need the maths to turn a crude understanding into a precise solution. So, if you don't understand vectors, you'd better go back and revise them.

4. Mar 31, 2016

### LoveBoy

Path will be straight line .

5. Mar 31, 2016

### LoveBoy

As per your directions given in last post,

Now, how do i find out relationship between them ?

6. Mar 31, 2016

### PeroK

What you have there is a "parametric" equation for $x$ and $y$. That means both $x$ and $y$ are expressed in terms of a common variable - in this case $t$ or $t/m$ if you prefer. You could plot those on a graph. $t/m = 0, 1, 2, 3 ...$ and see whether that nails down the option between A) to D).

7. Mar 31, 2016

### LoveBoy

By plotting the graph, i got
s_x and s_y path is parabolic.

8. Mar 31, 2016

### PeroK

That's right. Once you got going with this problem, you seemed to know what you were doing all right.