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PDE + shock

  1. Apr 5, 2006 #1
    PDE + shock !!!

    Ux + 2Uy = 0

    I.C: U(x,y=2x) = exp(x)

    solution:-
    y=2x+c1
    x=c2
    using I.C
    c1=0
    c2=exp(x)

    No solution since I.C on the characteristics line

    every thing is ok until here but my teacher said that there exist one case that when u change some thing u will get a solution

    how !!!!




    also i want 2 know why discont. or shock occur ???


    i hope u can help me

    :smile:
     
  2. jcsd
  3. Apr 6, 2006 #2

    Tom Mattson

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    Can you be more specific? I'm not following you.

    Also could you not use "chat room" slang? It took me a while to figure out that "u" means "you" and not the solution to the PDE. Thanks.
     
  4. Apr 7, 2006 #3
    Also could you not use "chat room" slang? <--- Sorry !!!

    Can you be more specific? <--- ok

    For the PDE there is no solution except one case, what is this case ?
    the proffisor said you can change something to have that case
     
  5. Apr 7, 2006 #4

    dextercioby

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    If i'm not mistaking, should the characteristics' eq be

    [tex] x+2y=C [/itex] ...?

    Daniel.
     
  6. Apr 7, 2006 #5
    ok ill try it then ill tell you the result

    thnx
     
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