BeiW
- 7
- 0
I'm a total physics noob, and as I was reading my physics textbook, I came upon this stump.
I know that for waves, Vmax2=(A)(square root of k/m). Does this apply to a pendulum because its motion is wavelike?
If so, how does the spring constant k play into this when the pendulum has no spring?
I know that for waves, Vmax2=(A)(square root of k/m). Does this apply to a pendulum because its motion is wavelike?
If so, how does the spring constant k play into this when the pendulum has no spring?