Percentage saving in weight of sloid shaft Vs hollow shaft

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To calculate the percentage saving in weight when replacing a solid shaft with a hollow shaft, the volume of both shafts must be determined using their respective cross-sectional areas. The hollow shaft's internal diameter is set at 60% of its external diameter, which affects its cross-sectional area and thus its volume. By maintaining constant length, material, and maximum shear stress, the weight savings can be derived by comparing the volumes of the solid and hollow shafts. Relevant equations include those for the volume of a solid cylinder and a hollow cylinder. This approach will yield the percentage reduction in weight when transitioning from a solid to a hollow shaft.
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I have calculated the external diameter and the solid shaft is to be replaced by a hollow shaft whose internal diameter equals 60% of the external diameter, the length, material, and maximum shear stress remaining unchanged.

How can I calculate the percentage saving in weight?
What are the equations that are relative to this?

Thank u for ur help
 
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adam333 said:
I have calculated the external diameter and the solid shaft is to be replaced by a hollow shaft whose internal diameter equals 60% of the external diameter, the length, material, and maximum shear stress remaining unchanged.

How can I calculate the percentage saving in weight?
What are the equations that are relative to this?

Thank u for ur help

Hi adam333! Welcome to PF! :smile:

Hint: volume = cross-section-area times height …

so how much is the cross-section-area reduced? :wink:
 
adam333: For the hollow versus solid shaft, hold applied torque and maximum shear stress constant, and set inside diameter of the hollow shaft equal to 60 % of the outside diameter of the hollow shaft. List relevant equations, and show your work.
 
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