Period of a simple harmonic oscillator

AI Thread Summary
The discussion focuses on calculating the new period of oscillation for a skydiver system when a second skydiver is added. The initial period of the first skydiver is 1.50 seconds, and the expected new period with an additional 60.0 kg skydiver is 1.94 seconds. The user struggles with applying the formula for the period of a simple harmonic oscillator, T = 2π√(m/k), and has received incorrect results. They request assistance with calculations and clarification on the method. The conversation highlights the importance of understanding the relationship between mass and period in harmonic motion.
spraymonkey32
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Hi I'm having problems with solving this question:
a 90.0 kg skydiver hanging from a parachute bounces up and down with a period of 1.50 seconds. What is the new period of oscillation when a second skydiver, whose mass is 60.0 kg, hangs from the legs first?

the answer is 1.94 seconds


Homework Equations


I think it has something to do with the the simple harmonic oscillator:
T = 2 (pi) sqrt(m/k)
I also tried the simple harmonic equation involving sin:
y=sinAwt=Asin sqrt(k/m)t

but i keep on getting 0.129 seconds.


I attempted this several times and is stuck on how to do it. I am studying for exams and there are several questions similar to it. Can someone help me please! :)
 
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Can you show your calculations for the T = 2π... method?
 
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