Period of Oscillation for a Standing Transverse Wave on a Flexible String

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The discussion centers on calculating the period of oscillation for a standing transverse wave on a flexible string, which is 1.52 m long, under a tension of 4.00 N, and has a mass of 10.81 g. The calculated wave velocity is 23.715 m/s, leading to a wavelength of approximately 1.01333 m for 1.5 waves. The initial period calculation of 0.0427 seconds is debated, with clarification needed on the wave configuration at the string's ends. Participants confirm that the period calculation appears correct if the string indeed supports 1.5 wavelengths. The conversation emphasizes the importance of accurately identifying wave characteristics to ensure correct calculations.
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A snapshot of a standing transverse wave on a flexible string is taken when the displacement is at a maximum showing two trough's and two peaks(1.5 waves). The string is 1.52 m long with tension 4.00 N. The total mass of the string is 10.81 g. Find the period of the oscillation.

I found the velocity to be 23.715m/s
So then I took the length of the string and divided it by the number of waves which was 1.5 and I got 1.01333.
Then to find the period I divided the 1.01333 by 23.715 to get 0.0427s, but it isn't right I don't get what I am doing wrong help please...
 
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two trough's and two peaks(1.5 waves)

isn't "two troughs and two peaks 2 complete waves (not 1.5)?
 
It is 1.5 waves because from peak to peak is one wave
 
Your answer 0.0427s looks correct to me, if it is 1.5 wavelengths on the string.

Just to clarify something: is one end of the string right at a peak, and the other end right at a trough? Or is each end of the string at the "zero point" (neither a peak nor a trough)?
 

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