Person in cart traveling down a valley

  • Thread starter Thread starter redworld33
  • Start date Start date
  • Tags Tags
    Cart
Click For Summary
To find the apparent weight of a person in a cart at the bottom of a valley, the net force equation Fnet = Fn - Fg is used, where Fn is the normal force and Fg is the gravitational force. The correct approach involves calculating the centripetal force required for circular motion, given by F = (V^2/r) * (m1 + m2). The user expresses confusion about their calculations, specifically regarding the interpretation of apparent weight and its representation in the context of the problem. Clarification is sought on the apparent weight concept, indicating a need to reassess the relationship between forces at play. Understanding apparent weight as the normal force experienced by the person is crucial for solving the problem accurately.
redworld33
Messages
4
Reaction score
0

Homework Statement



A 60 kg person rides in a 20 kg cart
moving at 13 m/s at the bottom of a valley that is in the shape of an arc of a circle
with a radius of 36 m. What is the apparent weight of the person as the cart passes
the bottom of the valley?

Homework Equations



F=ma
F=(V^2/r) * (m1 + m2)

The Attempt at a Solution


Fnet = Fn - Fg
m(V^2/r) - mg
80(169/36) - 80(9.8)
= -408.44
...im stuck. I don't feel like this is right and I don't know where I really went wrong
 
Last edited:
Physics news on Phys.org
You have the right equations and all, but take a step back for a second. In the context of the problem, what does apparent weight represent? What quantity represents it?
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

Replies
13
Views
2K
Replies
18
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 24 ·
Replies
24
Views
3K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 17 ·
Replies
17
Views
6K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
3
Views
9K
  • · Replies 11 ·
Replies
11
Views
3K