Phase difference after passing through liquid and glass

AI Thread Summary
To determine the phase difference between two waves traveling through different mediums, the key is to calculate the time taken for each wave to reach the finish line. Wave A travels through a glass container and liquid, while Wave B travels through a vacuum. The refractive indices for glass (n = 1.52) and liquid (n = 1.33) affect the speed and wavelength of Wave A. The phase difference can be expressed as Δφ = Δt, where Δt is the time difference calculated using the modified wavelengths in each medium. The solution requires careful consideration of the equations and dimensions involved to ensure accurate results.
magnesium12
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Homework Statement


Two waves travel next to each other for 100cm.
Wave A passes through a glass container containing liquid. The thickness of the glass in total is 1cm and the width of the liquid is 10cm. The glass has n = 1.52 and the liquid has n=1.33.
Wave B passes through a vacuum and has wavelength 500nm.
Both waves start out in phase. Find the relative phase differences at the finishing line (after 100cm).

Homework Equations


c/n = λv (?)

The Attempt at a Solution


I'm not sure where to start.
I was thinking that the phase difference will be proportional to the difference in time it takes to get to the finish line.
Δφ = Δt
But I have no idea how to find the difference in the time it takes for each wave to get to the end.
 
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You need to rethink (or look up) your equations. Dimensions don't match in both cases !
 
BvU said:
You need to rethink (or look up) your equations. Dimensions don't match in both cases !

So I found this: Δφ/2π = Δt/vo
And then t = c/λ and I find the new wavelength for each section of path B with c/nv and then add up the times?
 
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