Phase difference of 2 points in a same graph

AI Thread Summary
The discussion centers on understanding the phase difference between two points, O and P, in a wave graph. It emphasizes that the displacement of point P should not be represented as Asin(wt + 2pi/(x)) because P lags behind O in time. An analogy of corks floating on ocean waves illustrates that while O is falling, P will follow after a certain time delay. The conversation also touches on the convention of defining positive and negative displacement directions, clarifying that the motion is described as A.sin(ωt). Ultimately, the key takeaway is that any motion of O is mirrored by P after a time delay, regardless of the wave's instantaneous behavior.
kelvin macks
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Homework Statement



since point P is ahead of point O, why the displacement , y , of P shouldn't be Asin(wt + 2pi/(x)) ?

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Be careful, the graph is against x not t.
 
Jilang said:
Be careful, the graph is against x not t.

sorry, stil don't unseratand . can you explain further?
 
kelvin macks said:

Homework Statement



since point P is ahead of point O, why the displacement , y , of P shouldn't be Asin(wt + 2pi/(x)) ?
Think of the figure as a snapshot photo of an ocean swell.

Imagine O and P are corks floating on the ocean, and they rise and fall as the wave gently passes. At the moment captured in the photo, cork O is falling and crossing the zero line. How far must the wave move along (sliding along to the right) before cork P in turn finds itself falling through the zero line?

So P is lagging O by ...?
 
NascentOxygen said:
Think of the figure as a snapshot photo of an ocean swell.

Imagine O and P are corks floating on the ocean, and they rise and fall as the wave gently passes. At the moment captured in the photo, cork O is falling and crossing the zero line. How far must the wave move along (sliding along to the right) before cork P in turn finds itself falling through the zero line?

So P is lagging O by ...?

so are you assuming falling downward dispalcement is positive? floating upward dispalcement is negative since you said P is lagging behind by O. how do we know which direction is positive and which is negative (falling downward or floating upward) ?
 
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kelvin macks said:
so are you assuming falling downward dispalcement is positive?
Defintely not assuming anything. I described how you could see things were you to imagine this as an ocean swell; I used an analogy.

Floating upward dispalcement is negative since you said P is lagging behind by O. how do we know which direction is positive and which is negative (falling downward or floating upward) ?
You are told that movement is described as A.sin(ωt), so that's where you might choose/assume '+' direction if it's not explicitly indicated.

Any and every motion of O will be emulated at a time Δt later by a point which lags O by that amount of time, regardless of what that instantaneous motion of the sinusoid may be. Whatever O is doing will be copied by P a short time later.
 
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