Photoelectric and Compton Effects question

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SUMMARY

The discussion focuses on the relationship between temperature and radiation in the context of the photoelectric and Compton effects. As the temperature of a body increases, the frequency of peak intensity shifts to higher frequencies, resulting in a color change from red to white. The total power emitted by a hot body increases with the fourth power of its Kelvin temperature. The Compton effect is illustrated through an experiment where X-rays scatter off a target, demonstrating that the energy and momentum lost by the photon during the collision with an electron differ when a proton is involved instead.

PREREQUISITES
  • Understanding of electromagnetic radiation and its properties
  • Familiarity with the photoelectric effect and Compton effect
  • Knowledge of emission spectra and temperature effects on radiation
  • Basic principles of energy and momentum conservation in collisions
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  • Study Planck's Law and its implications for blackbody radiation
  • Learn about the mathematical formulation of the Compton effect
  • Investigate the relationship between temperature and radiation in detail
  • Explore experimental setups for observing the photoelectric and Compton effects
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pharaoh
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As the temperature of a body is increased, how
does the frequency of peak intensity change? How
does the total amount of radiated energy change?


When the dimmer control is used to increase the voltage to the bulb, the
temperature of the glowing filament increases. As a result, the color changesfrom deep red to orange to yellow and finally, to white. This color change occurs because the higher-temperature filament emits higher-frequency radiation.
The higher-frequency radiation comes from the higher-frequency end
of the visible spectrum (the violet end) and results in the filament appearingto be whiter. A plot of the intensity of the light emitted from a hot body over a range of frequencies is known as an emission spectrum. at each temperature, there is a frequency at which the maximum amount of energy is emitted. as the temperature increases, the frequency at which the maximum amount of energy is emitted also increases.
The total power emitted by a hot body also increases with temperature.
The power (the energy emitted per second) of an electromagnetic wave is
proportional to the hot body’s kelvin temperature raised to the fourth
power. Thus, hotter bodies radiate considerably more power than do
cooler bodies. Probably the most common example of a hot body radiating
a great amount of power is the Sun, a dense ball of gases heated to
incandescence by the energy produced within it.


An experimenter sends an X ray into a target. An electron,
but no other radiation, emerges from the target.
Explain whether this event is a result of the photoelectric
effect or the Compton effect.


Compton directed X rays of a known wavelength at a target, and
measured the wavelengths of the X rays scattered by the target. some of the X rays were scattered without change in wavelength, whereas others had a longer wavelength than that of the original radiation.
Note that the peak wavelength for the unscattered X rays corresponds to the wavelength of the original incident X rays, whereas the peak wavelength for the scattered X rays is greater than that of the original incident X rays.

Am I right?


Imagine that the collision of
two billiard balls models the interaction of a
photon and an electron during the Compton effect.
Suppose the electron is replaced by a much more
massive proton. Would this proton gain as much
energy from the collision as the electron does?
Would the photon lose as much energy as it does
when it collides with the electron?


(this question I couldn't figure it out)
but i will guess and say, Much like the
collision between two billiard
balls, when a photon strikes
an electron, the energy and
momentum gained by the electron
equal the energy and momentum
lost by the photon
 
Last edited:
Physics news on Phys.org
. In thisscenario, if the electron is replacedby a more massive proton, the protonwould still gain the same amount ofenergy from the collision as the electron does,but the photon would lose less energy than whenit collides with the electron.
 

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