Photoelectric and Compton Effects question

In summary: This is because the proton has a greater mass and therefore, requires more energy to change its momentum compared to the electron. Therefore, the change in energy for the photon would be less when colliding with the proton compared to the electron. In summary, as the temperature of a body increases, the frequency of peak intensity also increases and the total amount of radiated energy emitted also increases. This is due to the higher-temperature filament emitting higher-frequency radiation, resulting in a change of color from red to white. The emission spectrum of a hot body shows the frequency at which the maximum amount of energy is emitted, which also increases with temperature. The power emitted by a hot body also increases with temperature, with the power being proportional to the hot body
  • #1
pharaoh
49
0
As the temperature of a body is increased, how
does the frequency of peak intensity change? How
does the total amount of radiated energy change?


When the dimmer control is used to increase the voltage to the bulb, the
temperature of the glowing filament increases. As a result, the color changesfrom deep red to orange to yellow and finally, to white. This color change occurs because the higher-temperature filament emits higher-frequency radiation.
The higher-frequency radiation comes from the higher-frequency end
of the visible spectrum (the violet end) and results in the filament appearingto be whiter. A plot of the intensity of the light emitted from a hot body over a range of frequencies is known as an emission spectrum. at each temperature, there is a frequency at which the maximum amount of energy is emitted. as the temperature increases, the frequency at which the maximum amount of energy is emitted also increases.
The total power emitted by a hot body also increases with temperature.
The power (the energy emitted per second) of an electromagnetic wave is
proportional to the hot body’s kelvin temperature raised to the fourth
power. Thus, hotter bodies radiate considerably more power than do
cooler bodies. Probably the most common example of a hot body radiating
a great amount of power is the Sun, a dense ball of gases heated to
incandescence by the energy produced within it.


An experimenter sends an X ray into a target. An electron,
but no other radiation, emerges from the target.
Explain whether this event is a result of the photoelectric
effect or the Compton effect.


Compton directed X rays of a known wavelength at a target, and
measured the wavelengths of the X rays scattered by the target. some of the X rays were scattered without change in wavelength, whereas others had a longer wavelength than that of the original radiation.
Note that the peak wavelength for the unscattered X rays corresponds to the wavelength of the original incident X rays, whereas the peak wavelength for the scattered X rays is greater than that of the original incident X rays.

Am I right?


Imagine that the collision of
two billiard balls models the interaction of a
photon and an electron during the Compton effect.
Suppose the electron is replaced by a much more
massive proton. Would this proton gain as much
energy from the collision as the electron does?
Would the photon lose as much energy as it does
when it collides with the electron?


(this question I couldn't figure it out)
but i will guess and say, Much like the
collision between two billiard
balls, when a photon strikes
an electron, the energy and
momentum gained by the electron
equal the energy and momentum
lost by the photon
 
Last edited:
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  • #2
. In thisscenario, if the electron is replacedby a more massive proton, the protonwould still gain the same amount ofenergy from the collision as the electron does,but the photon would lose less energy than whenit collides with the electron.
 
  • #3
.
If a proton is substituted for the electron, the proton being more massive will not gain as much energy as the electron did in the collision. The photon will also not lose as much energy as it did in the collision with the electron. This is because the proton's larger mass will affect the transfer of energy and momentum, resulting in a smaller change for both the proton and the photon. However, the exact amount of energy and momentum gained or lost will depend on the specific properties of the proton and the photon involved in the collision.
 

Related to Photoelectric and Compton Effects question

1. What is the photoelectric effect?

The photoelectric effect is the phenomenon in which electrons are emitted from a material when it is exposed to light of a certain frequency.

2. How does the photoelectric effect work?

When a photon of light with enough energy hits a material, it knocks an electron off of an atom in the material. This electron then becomes a free electron and can move through the material.

3. What is the Compton effect?

The Compton effect is the scattering of photons by electrons. It is a result of the interaction between photons and electrons, and it causes a shift in the wavelength of the scattered photons.

4. How is the Compton effect related to the photoelectric effect?

The Compton effect is related to the photoelectric effect because both involve the interaction between photons and electrons. However, the photoelectric effect results in the emission of electrons, while the Compton effect results in a change in the wavelength of the scattered photons.

5. What are the applications of the photoelectric and Compton effects?

The photoelectric effect is commonly used in technologies such as solar panels and photomultiplier tubes. The Compton effect has applications in medical imaging, such as in X-ray and CT scans, as well as in nuclear physics research.

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