Photoelectric effect experiment

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Systematic and random errors in a photoelectric effect experiment can significantly impact results, particularly when measuring the stopping voltage against photon frequency. Key sources of error include calibration drift, hysteresis, and potential inaccuracies in the photodiode's response to varying light frequencies. Environmental factors, such as temperature fluctuations and electromagnetic interference, may also affect measurements. The experiment's design and apparatus specifics are crucial for identifying additional error sources. Understanding these factors is essential for accurately comparing experimental values of Planck's constant to established ones.
chialer96
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What are the possible systematic/random error that can affect my experimental results?
 
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Unless you give us more details on the goal of the experiment and the nature of the apparatus, the only answer you can get is "lots".
 
Photoelectric effect experiment. Light with different frequencies are shone onto a photodiode therefore a current is produced. We apply a stopping voltage to the current to cease the kinetic energy of electrons. Stopping voltage is plotted against frequency of photons. The graph will cut at a y intercept which we knownas work function. Now we compared our experimental value of Planck's constant to the actual one. Obviously we will get a percentage error. Now I need help with the possible errors
 
This may be a good start: http://www.oufusion.org.uk/index.php/component/content/article/1-features/2-einstein-millikan-and-the-photoelectric-effect
 
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Anymore ideass other than calibration driftingor hysteris
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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