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Photoelectric effect, h/e ratio

  1. Apr 16, 2007 #1
    1. The problem statement, all variables and given/known data

    From the following graph determine the experimental value of the h/e ratio and the work function of the metal. ( 1 Joule = 6.242 x 1018 eV )

    [​IMG]

    The work function Wo in eV from the y-intercept of the stopping voltage Vs vs. frequency f graph = ______ eV

    I already found the slope (h/e value) to be 3.73e-15 V*s which is correct according to the the online homework.

    2. Relevant equations

    I would assume that all I need is e = 1.60e-19 C to get eV from V.

    3. The attempt at a solution

    The Y-int appears to be around .64 V (I used this value to help get the slope so it should be correct) so I multiply that by e to get 1.02e-19 eV. However, this answer is not correct, what am I doing wrong?
     
  2. jcsd
  3. Apr 17, 2007 #2

    andrevdh

    User Avatar
    Homework Helper

    You read the y intercept off at [tex]5 \times 10^{14}\ Hz[/tex]!
     
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