Physical applications of complex numbers

Calpalned
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Homework Statement


upload_2015-10-13_18-59-28.png


Homework Equations


see picture above

The Attempt at a Solution


I can follow most of the steps, but not all. I got confused with finding ##|\frac{dz}{dt}|##. It is easy to derive ##\frac{dz}{dt}## from ##z##. Normally, I would square the two components of ##dz/dt## and take the square root to get the magnitude (velocity), but here I don't have the components. Is it a general rule that if I don't have the components of a vector, to find the magnitude, I multiply by the complex conjugate?
 
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Calpalned said:

Homework Statement


View attachment 90171

Homework Equations


see picture above

The Attempt at a Solution


I can follow most of the steps, but not all. I got confused with finding ##|\frac{dz}{dt}|##. It is easy to derive ##\frac{dz}{dt}## from ##z##. Normally, I would square the two components of ##dz/dt## and take the square root to get the magnitude (velocity), but here I don't have the components. Is it a general rule that if I don't have the components of a vector, to find the magnitude, I multiply by the complex conjugate?
For a complex number z, ##|z| = \sqrt{z \cdot \bar{z}}##
 
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What is the physical difference between ##|\frac{dz}{dt}|## and ##\frac{dz}{dt}## Could you please give a real world example (ie a car, horse, etc moving) Thank you.
 
Calpalned said:
What is the physical difference between ##|\frac{dz}{dt}|## and ##\frac{dz}{dt}## Could you please give a real world example (ie a car, horse, etc moving) Thank you.
A car's speedometer gives the magnitude of the car's velocity. For example, if you drive the car around a circle at a constant speed, the speedometer needle doesn't change. Velocity is a vector quantity, so the direction of the velocity vector is changing while the car is turning, even though the speed (|v|) is not.
 
Mark44 said:
A car's speedometer gives the magnitude of the car's velocity. For example, if you drive the car around a circle at a constant speed, the speedometer needle doesn't change. Velocity is a vector quantity, so the direction of the velocity vector is changing while the car is turning, even though the speed (|v|) is not.
Thank you. I understand now that the magnitude of velocity is speed
 
Note that an object moving around a circle with constant speed has norm of the velocity vector constant so its derivative is 0. But the velocity vector is NOT constant so its derivative, the acceleration vector, is not 0.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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