Physics 20-1: Energy Homework Solutions

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For the physics homework on energy, the first problem involves calculating the average force of air resistance acting on a 0.25 kg pine cone that falls 20 m and hits the ground at 9.0 m/s. The discussion emphasizes using the relationship between work and force, as well as considering the change in kinetic energy. The second problem focuses on determining the final speed of a 12 kg mass in a pulley system, suggesting the use of conservation of energy principles. Participants recommend analyzing the forces on both boxes in the system to find the solution. Overall, the thread provides insights into applying mechanical work and energy conservation concepts for exam preparation.
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Homework Statement


a) A 0.25 kg pine cone falls from a branch 20 m above the ground. if it actually hits the ground with a speed of 9.0m/s, what was the average force of air resistance exerted on it?

b) For the pulley system illustrated to the right, when the masses are released, what is the final speed of the 12kg mass just before it hits the floor?

* the diagram is basically a 4.0 kg box at rest on the floor with a rope attached to it, the rope is thrown over a pulley, and attached to the hanging 12 kg box. the total distance that the 12 kg box travels is 5.0m.

Homework Equations


i have for a) W = F d and for b) Ep = mgh, Ek = 1/2mv^2

The Attempt at a Solution


i have no idea how to get started.
 
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For the first you have to use that the air resistance force, is proportional to the square of the velocity in this case.
For the second one, just use conservation of energy
 
For the first you have to use that the air resistance force, is proportional to the square of the velocity in this case.
For the second one, just use conservation of energy
 
For a)
consider other definitions of mechanical work. e.g. the change in kinetic energy.

A starting point for b) should be to consider the forces acting on each box
 
thx guys! i figured them both out. now i just need to be able to apply them in my exam today xD
 
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