Solving Dynamics Problems with Forces, Work, and Energy

  • Thread starter Thread starter Pepsi
  • Start date Start date
  • Tags Tags
    Dynamics Physics
AI Thread Summary
The discussion focuses on solving dynamics problems involving forces, work, and energy. A user seeks help with two specific physics questions related to a 25 N force applied to a 15 kg object and a cart experiencing friction. Solutions are provided using both the work-energy principle and Newton's second law, emphasizing the calculation of work done and final velocity. The user confirms their calculations, arriving at 43.2 J for the work done and 33 m/s for the cart's final velocity. The thread concludes with a request for verification of these results.
Pepsi
Messages
14
Reaction score
0
I have been absent from my physics class for the past week due to an illness, and now am having troubles with some of my workbook questions. There are two in particular which my teacher had told me to know how to do as they would be on my test in the next few days.

the ones he wrote out were... a 25 n force will accelerate a 15kg object over a horizontal and low friction surface from rest to 2.4 m/s in 1.4 s find the work done on the object. and

a 25 n force is applied to a 15kg cart where the force of friction is 8.5N the distance traveled is 16.5 m the cart starts from a dead stop. Determine the carts final velocity using its kinetic energy. any help would be great.
 
Physics news on Phys.org
a 25 n force will accelerate a 15kg object over a horizontal and low friction surface from rest to 2.4 m/s in 1.4 s find the work done on the object.
There are two ways to do this.
The hard way: You know the force and the mass so you can find the acceleration (F= ma). Once you know that, you know how far the object went in 1.4 s and work= force* distance.

The easy way: You know that the object had initial speed 0 so initial kinetic energy 0. You know the mass and final speed so you can calculate the final kinetic energy- kinetic energy= (1/2)*mass*velocity2. That change in kinetic energy IS the work the force did on the object.

a 25 n force is applied to a 15kg cart where the force of friction is 8.5N the distance traveled is 16.5 m the cart starts from a dead stop. Determine the carts final velocity using its kinetic energy.

You know the applied force and you know the friction force so you can subtract to get the "net" force. You know the distance the force was applied and work equals force times distance so you can calculate the work done on the object. That work is converted into kinetic energy and kinetic energy equals (1/2)*mass*velocity2.
 
wow thanks a lot, I'm doing the two questions as we speak and having no problems at all. :smile:
 
just to double check the first question is 43.2 J, and the second 33 m/s?

please confirm or if if I'm wrong tell me.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top