Physics distance and acceleration Problems

AI Thread Summary
Marcus's car accelerates to overtake Melissa's car, which is initially 200 meters ahead. The calculations show conflicting results for acceleration, with one participant finding it to be 0.46 m/s² and another suggesting 3.44 m/s². The time taken for Marcus to overtake Melissa is given as 12 seconds. The discussion emphasizes the importance of clearly presenting calculations and diagrams for accurate assistance. Overall, the correct acceleration and distance traveled by Marcus remain unresolved.
Dhooy7
Messages
33
Reaction score
0

Homework Statement



What acceleration does Marcus feel and how long does Marcus travel with the details: Marcos and Melissa are driving. Marcus's car travels 21 m/s and Melissa's travels 25 m/s. Marcus's car is 200 m behind Melissa's car when he hits the gas, giving constant acceleration. Marcus overtakes 12 sec?

Homework Equations

The Attempt at a Solution

 

Attachments

  • physics d1.jpg
    physics d1.jpg
    8.3 KB · Views: 450
  • physics distance.jpg
    physics distance.jpg
    8 KB · Views: 503
Last edited by a moderator:
Physics news on Phys.org
Dhooy7 said:

Homework Statement



What acceleration does Marcus feel and how long does Marcus travel with the details: Marcos and Melissa are driving. Marcus's car travels 21 m/s and Melissa's travels 25 m/s. Marcus's car is 200 m behind Melissa's car when he hits the gas, giving constant acceleration. Marcus overtakes 12 sec?

Homework Equations

The Attempt at a Solution


Welcome to the PF.

Those images are really hard to see. Can you please type your solution into the forum, so it is easier for us to help you? Thanks.
 
It is far preferable that you type details of your method and working, so respondants can read it easily and quote parts of it in their reply.

Presumably you post here hoping for assistance? So ... by making that effort you'll make it easy for people to help you.

I see you are new here so , http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif
 
Last edited by a moderator:
I got delta x=285.12 m
a=0.46

I did it another way with someone else and he said a=3.44 m/s and x=500m. Not sure which is right.
 
Mellia=Marcu's distance +200m.

I used vf2=vo2+2a (200m) and solved for a.
vf=25
vo=21
t=12

Then used delta x =vot+1/2at2
 
Mellia=Marcu's distance +200m
Check this. Whose car will travel the greatest distance after we start observing them?

Your equation seems to be solving for Marcu's car to attain 25 m/s when it reaches Mellia's starting point (being 200m from where he started).
EDITED
 
Last edited:
So what is the right answer?
 
Your working is not correct. Try drawing a clear diagram that fits the scenario you are examining.
 
So neither of these are correct:

a=3.44 m/s and x=500m.

I got delta x=285.12 m
a=0.46
 
Back
Top