Physics + Logic = tired brain :biggrin:

AI Thread Summary
A college rower can push a small car along a flat road due to the force of friction being easier to overcome than the force of gravity when lifting the car. The frictional force is calculated using the coefficient of friction multiplied by the normal force, while the gravitational force is determined by the mass of the car and acceleration due to gravity. The discussion emphasizes comparing the forces required for pushing versus lifting the car, highlighting that the frictional force is generally less than the gravitational force. Participants suggest estimating the coefficient of friction to further understand the mechanics involved. Overall, the discrepancy between the two scenarios is rooted in the difference in forces acting in the respective directions.
kristen151027
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This one should be quick and easy, but I just can't seem to get it:

"A college rower can easily push a small car along a flat road, but she cannot lift the car in the air. Since the mass of the car is constant, how can you explain this discrepancy?"

Edit: I'm thinking that friction can be overcome more easily than gravity...but I'm struggling to prove that.
 
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Think about the forces that are acting. What is the difference in direction between lifting it up, and pushing it across?
What are the forces acting in these directions?
 
Sorry, just read your edit... remember friction force is given by mu * N
(normal force). Where mu is the co-efficient of friction - you might be able to estimate this, or find an approximate value somewhere.
The force acting due to gravity is F=mg.
I hope this gives you enough to go on with...
 
tyco05 said:
Sorry, just read your edit... remember friction force is given by mu * N
(normal force). Where mu is the co-efficient of friction - you might be able to estimate this, or find an approximate value somewhere.
The force acting due to gravity is F=mg.
I hope this gives you enough to go on with...

Yes, thank you! :biggrin:
 
The force to lift the car up is F = m.g.
The force to push the car along a flat road is F > \mu_s.m.g

Compare this two forces.

HINT: Between what values is usually \mu_s.
 
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