Solving Physics Problems - Aiming a Gun at a Target

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A hunter aiming directly at a target 100m away with a bullet speed of 250m/s will miss the target by 39.2m due to the bullet's drop from gravity. The time taken for the bullet to reach the target is calculated to be 0.4 seconds. To hit the target, the gun must be aimed at an angle that compensates for this drop, requiring the calculation of the initial vertical velocity component. By determining the time it takes for the bullet to travel horizontally to the target, the necessary angle can be derived to ensure the bullet reaches the same vertical level as the target. Properly solving for both parts involves applying kinematic equations for projectile motion.
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physics problem...

A hunter aims directly at a target (on the same level) 100m away.
a) If the bullet leaves the gun at a speed of 250m/s, by how much will it miss the target?
b) At what angle should the gun be aimed so the target will be hit?

Any help would be great. Thanks.
 
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What have you done so far?
 
I set up the axis where the hunter is Y meters up and the target is also Y meters up to 100m to the right.
The X component of the velocity is 250m/s and Y component is 0.

For part a)
I used the distance formula in the Y and X components so:
Y = Yi + vi*t + 1/2*a*t^2.
X = Xi + vi*t + 1/2*a*t^2.

Y=0
Vi=0
Xi=0
a in the X component = 0

From the X component of the distance formula I solved for time =0.4s.
Then I plug in the time into the Y component of the distance formula and got 39.2m.

I'm not sure where to start for part b).
 
Note that given initial speed V0, and angle a to the horizontal, we may write:
Initial horizontal velocity: V0cos(a)
Initial vertical velocity: V0sin(a)

Find the time T from the horizontal component (that is, which yields final horizontal position equal to 100)
Determine a by requiring that at this time T, final vertical position must be zero (equal to initial level)
 
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