Physics- velocity/ distance problem?

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The discussion focuses on solving a physics problem involving an object with a time-dependent acceleration given by a = Bt^2 - 1/2Ct. The user is attempting to find the object's velocity and distance after 7.5 seconds but is struggling with the integration process. It is clarified that the equation v = at is only valid for constant acceleration, and since the acceleration here is time-dependent, integration of the acceleration function is necessary. Participants suggest integrating the acceleration equation and using the resulting function to determine velocity at t = 7.5 seconds. The key takeaway is that proper integration is essential for solving the problem due to the variable nature of acceleration.
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Homework Statement



An object starts from rest and has an acceleration given by
a = Bt^2 − 1/2Ct, where B = 4.5 m/s^4 and C = −2.2 m/s^3

(1) What is the object's velocity after 7.5 s? (Indicate the direction with the sign of your answer.)

(2) How far has the object moved after t = 7.5 s?


Homework Equations



v=at


The Attempt at a Solution



I integrated the equation its not coming out right

what am i doing wrong?

If someone can kindly explain.

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Hint
v=at is valid if acceleration is not time dependent (i.e. it is constant)
 
So, I am using the wrong equation? What equation should i use?
 
you have to integrate the equation not differentiate
 
So i have to integrate a= Bt^2- 1/2Ct?

Do i substitute the answer in equation v=at? Or i can't use that equation at all since a is time dependent.

Can you show some work so I have a better idea?
 
Last edited:
We derive the equation v=u+at assuming that acceleration is constant.
here acceleration is time dependent
dv/dt = a
dv=adt
substitute a with the equation you have
integrate both sides of the equation with limits 0 to v and 0 to t respectively
after this you get an equation of v as a funtion of time.
substitute t=7.5s in this equation to get velocity at that time.
 
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