What does liquid helium look like?

AI Thread Summary
Liquid helium is a colorless and transparent liquid with a boiling point of -452.1 degrees Fahrenheit (-269 degrees Celsius), resembling water but at an extremely low temperature. It is primarily used in scientific research and medical applications for cooling purposes. Capturing a clear image of liquid helium is challenging due to its transparency, but images of it in containers or with supercooled objects can be found online. Additionally, videos demonstrating its properties may aid in understanding its appearance and behavior. Overall, while difficult to visualize, liquid helium plays a crucial role in various scientific fields.
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I need a picture of liquid helium itself for my project on superconductors. I've looked all over but I can't find anything
 
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I couldn't find any on Google in the first few pages.

AFAIK, it just looks like water (only you'd freeze to death instantly if you drank it).

You may do a search for "Bubble Chamber"

Bubble chamber sub-atomic particle tests were done in liquid helium. The picture will be a lot prettier than a pool of something that looks like smoking water.
 
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Liquid helium is a colorless and transparent liquid with a very low boiling point of -452.1 degrees Fahrenheit (-269 degrees Celsius). At this temperature, it appears as a clear, odorless liquid with a density approximately 1/8th of water. Due to its extremely low temperature, it is often used to cool materials and equipment in scientific research and medical applications.

Unfortunately, since it is a colorless and transparent liquid, it is difficult to capture a clear image of liquid helium. However, you can find some images online that show the liquid helium in a container or a supercooled object immersed in it. These images can give you an idea of what liquid helium looks like. Additionally, you can also find videos online that show the properties and behavior of liquid helium, which may be helpful for your project.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

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