A fluid of density (rho) flows through a horizontal pipe with negligible viscosity. The flow is streamline with constant flow rate. The diameter of the pipe at Point 1 is d and the flow speed is v. If the diameter of the pipe at Point 2 is d/3, then the pressure at Point 2 is?(adsbygoogle = window.adsbygoogle || []).push({});

Bournalli's Equation (sp). I ended up getting P2=P1 - 40(rho)v^2. Correct?

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# Homework Help: Pipe Pressure

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