Planar Kinematics: Determine Angular Velocity of Plate BCD

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SUMMARY

The discussion focuses on calculating the angular velocity of plate BCD given the angular velocity of link AB at 7.6 rad/s and specific dimensions. The equations used include VB = VA + VB/A and VD = VE + VD/E, leading to a system of equations with two unknowns: the angular velocity of BCD and the angular velocity of BD. The correct angular velocity of plate BCD is confirmed to be +1.641 rad/s in the clockwise direction, resolving the initial confusion regarding the sign of the answer.

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Homework Statement


The link AB has an angular velocity of 7.6 rad/s in the direction shown.

http://hdimage.org/images/mg122xouxwua5jzgn110.jpg
Determine the angular velocity of plate BCD if the angles are as shown and AB = 58mm and BD = 111mm.

Homework Equations


VB = VA + VB/A

VD = VE + VD/E

VB/D = VB - VD

The Attempt at a Solution


I have made one long thought out attempt at this problem. Basically, I used the above equations, canceling out the velocity of the fixed points. Then by converting the velocities, to i and j components, I got two equations with 3 unknowns, 1. the angular velocity of BCD, 2. the angular velocity of BD and 3. the length BD. By simply counting the angular velocity of BD and the length BD as one unknown, I have 2 unknowns and two equations. My answer was 1.641 rad/s [clockwise]. But this answer is incorrect, any help would be greatly appreciated.
 
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Solved! The answer is +1.641.
 

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