Planar Kinematics: Determine Angular Velocity of Plate BCD

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The problem involves determining the angular velocity of plate BCD given the angular velocity of link AB at 7.6 rad/s and specific lengths. The equations of motion used include VB = VA + VB/A and VD = VE + VD/E, leading to a system of equations with two unknowns. An initial calculation yielded an angular velocity of 1.641 rad/s clockwise, which was later confirmed as correct. The solution emphasizes the importance of accurately applying kinematic equations and considering fixed points in the analysis. The final answer for the angular velocity of plate BCD is +1.641 rad/s.
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Homework Statement


The link AB has an angular velocity of 7.6 rad/s in the direction shown.

http://hdimage.org/images/mg122xouxwua5jzgn110.jpg
Determine the angular velocity of plate BCD if the angles are as shown and AB = 58mm and BD = 111mm.

Homework Equations


VB = VA + VB/A

VD = VE + VD/E

VB/D = VB - VD

The Attempt at a Solution


I have made one long thought out attempt at this problem. Basically, I used the above equations, canceling out the velocity of the fixed points. Then by converting the velocities, to i and j components, I got two equations with 3 unknowns, 1. the angular velocity of BCD, 2. the angular velocity of BD and 3. the length BD. By simply counting the angular velocity of BD and the length BD as one unknown, I have 2 unknowns and two equations. My answer was 1.641 rad/s [clockwise]. But this answer is incorrect, any help would be greatly appreciated.
 
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Solved! The answer is +1.641.
 
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