Plane polarized oscilation of a spring

AI Thread Summary
To determine the energy E of a spring oscillating in a pure second harmonic motion, the mechanical energy is the sum of kinetic energy (Ekin) and potential energy (Epot). The frequency Omega can be derived from the spring's elastic constant k and mass M, using the formula Omega = sqrt(k/M). The amplitude A of the oscillation is given as 1 meter, which influences both the kinetic and potential energy calculations. The total mechanical energy can be expressed as E = (1/2)kA^2, where A is the amplitude of oscillation. Understanding these relationships is crucial for accurately calculating the energy of the system.
DaTario
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Hi All,

Suppose you have a spring with a given elastic constant k. Its natural width is L = 1 meter and its mass is M = 0.1 kg. Now imagine you put this spring to oscilate, with its ends fixed, forming a pure second harmonic oscilation, plane polarized, with frequency Omega. The amplitude of this oscillation is A = 1 meter also.
How is one to determine the energy E of this system ? (mechanical energy of this system E = Ekin + Epot)

P.S. it seems natural that the frequency Omega is to be determined from the constants I alluded above.

P.S. 2: by second harmonic I mean a sine function between the end points (x = 0 and x = 1) with just one crest and one valley.

Best Regards

DaTario
 
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Best Regards

DaTario
 

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