Plate Capacitor: Find Voltage with 4\muC & 0.4m2 Area

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To find the voltage across a capacitor with an area of 0.4 m², a distance of 0.5 micrometers, and a charge of 4 µC, the capacitance can be calculated using the formula C = ε(A/d), where ε is the permittivity of free space (approximately 8.85 x 10^-12 F/m). After calculating the capacitance, the voltage can be determined using the equation ΔV = q/C. The user is struggling with the calculations and has requested assistance to clarify their process. Accurate calculations are essential for determining the correct voltage across the capacitor.
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Homework Statement



The plates of a capacitor have an area of 0.4m2 and are separated by a distance of 0.5 micrometers. The material between the two plates is air with a dielectric constant of 1.0 One plate of the capacitor is given the charge of 4\muC. The voltage across the capacitor is, in volts:

Homework Equations




C=\epsilon(A/d) C=q/\DeltaV

The Attempt at a Solution


So far I've been trying to calculate the capacitance with the first equation and then use the second equation for finding the change in voltage. I keep coming up with the wrong answer, though. Help please!
 
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Show your calculations.
 
(.4m2/.5\mum)x8.85E-12=C

C=q/\DeltaV
\DeltaV=q/C=4\muC/Capacitance
 
I just looked at my calculations and cnai just say sorry if they are a little garbled. I'm having trouble getting used to the way you do calculations on the website. Let me know if you would like me to do them again. Thanks!
 

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