Plate Capacitors (Velocity selector)

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SUMMARY

The discussion centers on calculating the maximum magnetic field strength that allows a test charge to escape a plate capacitor without colliding with the plates. The capacitor has one grounded plate and another initially set to a potential V, later adjusted to zero. The relationship between electric and magnetic forces is crucial, specifically the equation qvB = qE, which must be balanced. The geometry of the capacitor, including the length of the plates and their separation, plays a significant role in determining the trajectory of the charge.

PREREQUISITES
  • Understanding of plate capacitors and their configurations
  • Familiarity with the concepts of electric fields and magnetic fields
  • Knowledge of the equation qvB = qE and its implications
  • Basic geometry related to circular motion and trajectories
NEXT STEPS
  • Study the principles of electric fields in capacitors, focusing on grounded configurations
  • Learn about the effects of magnetic fields on charged particles in motion
  • Explore the geometry of circular motion to understand trajectory calculations
  • Investigate the relationship between electric and magnetic forces in more complex scenarios
USEFUL FOR

Physics students, electrical engineers, and anyone interested in the dynamics of charged particles in electromagnetic fields will benefit from this discussion.

yahoo32
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You have a plate capacitor which is grounded on the bottom and is held at a potential V which is then set to 0. You are given the length of the plates and the distances between them. A test charge is brought in with the charge and mass given along with its velocity. For a vanishing magnetic field the test charge just moves to the right on a straight line and escapes the capacitor. If you increase the magenetic field the trajectory will bend. The problem is to find the largest magnetic field (increasing the value from 0) such that the test still escapes the capacitor without crashing into the plates.

I am totally clue less on this problem but I think perhaps you must do soem geometry with the radius, the length of the plates and the distances between them and maybe some how incorporate the fact the qvB = qE (and balance that equation) ? But this is all I have been able to come up with, any help would be greatly appreciated!
 
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I think this problem is being ignored because some of the conditions don't seem to be stated very clearly. Are you saying that there is zero voltage across the capacitor? (Why is it even mentioned that one plate is grounded and the other is first set to some potential, but then to zero?) Is it the case that there is no electric field there? (In that case, what difference does it make that this is even a capacitor?)

Are you simply being asked to find the size of the magnetic field acting alone? Are you supposed to assume that the charged particle enters at mid-height between the plates? It seems that maybe this is just a geometry problem: if the plates have length L and separation s, and the particle starts out at a distance s/2 "above" one of the plates, you need to find the circular arc that will just miss the "far end" of the "lower" plate. The geometry of a circle will then tell you the minimum radius the circle may have, which in turn will let you find the stronger magnetic field that can be permitted for a particle of charge q and mass m.
 

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