1. The problem statement, all variables and given/known data What mass of ice at -10.0 degrees celsius is needed to cool a whale's water tank, holding 1.20 x 10^3 m^3 of water, from 20.0 degrees down to a more comfortable 10 degrees. 2. Relevant equations Q = mc *delta T Q = mL 3. The attempt at a solution i'm trying to fill out a table with knowns and unknowns before I actually solve the problem. This is what i got, can someone help me with the temperatures? ICE: mass = x c = 2090 J/kg C Ti = -10.0 Tf = 0 MELT: mass = x L = 3.33 x 10^5 ICE - WATER: mass = x c = 4190 This is where i'm stuck what's the temperature? Ti = ? Tf = ? WATER: mass = ?? c= 4190 Ti = 20.0 Tf = 10 Can someone let me know where i went wrong?? I still need to find the mass of water. Thanks!