Please help i've tried everything

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To determine the mass of steam at 150 degrees Celsius needed to heat 200g of water and a 100g glass container from 20 to 45 degrees Celsius, the relevant equation is Q=mc(delta)T. The calculation involves finding the energy required to first convert the steam to water at 100 degrees Celsius, then the energy needed to raise the temperature of the resulting water by 25 degrees. There is confusion regarding the conversion of steam to water and the specific values used in the calculations. Clarification on the energy transfer process and the correct application of the equation is necessary for an accurate solution. Understanding the complete thermal dynamics involved is crucial for solving the problem effectively.
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Homework Statement


What mass of steam initally at 150 degrees celcius is needed to warm 200g of water in a 100g glass container from 20 degrees celsius to 45 degrees celsius?


Homework Equations


I think Q=mc(delta)T


The Attempt at a Solution


using the above equation calculating the energy required to transfer the steam to 100 degrees and then the energy required to convert it to water and then the energy required to raise the water 25 degrees. That is not right though!
 
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That equation alone is not the whole story. What does "convert it to water" do? What values have you used in the equation and how have you used it?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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