How Do Excited Mercury Atoms Emit Light at 436 nm?

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Excited mercury atoms emit light at a wavelength of 436 nm, which corresponds to a specific frequency and energy of radiation. To calculate the frequency, the speed of light can be used along with the wavelength. The energy of the emitted light can be determined using Planck's equation, which relates energy to frequency. The discussion emphasizes the importance of relevant equations and constants in solving these types of problems. Understanding these concepts is crucial for accurately determining the properties of the emitted light.
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Excited mercury atoms emit light strongly at a wave of 436 nm (1 nm=10^-9m).
a.) What is the frequency of radiation?
b.) What is the energy of this radiation
c.) Good illustration of the electromagnetic spectrum
 
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VIPOWER said:
Excited mercury atoms emit light strongly at a wave of 436 nm (1 nm=10^-9m).
a.) What is the frequency of radiation?
b.) What is the energy of this radiation
c.) Good illustration of the electromagnetic spectrum

Welcome to the PF. We do not do your homework/coursework for you. What are the Relevant Equations? (There's a reason we ask for those in the Homework Help Template that you deleted from your post.)
 
Are any equations specified with your work? If not, have a look in your textbooks or online. When trying to pick equations to use remember what information you have and what you hope to get out of it. You only have one piece of information, the wavelength λ, perhaps there are some universal constants you can use to find your answers?
 
i.e. speed of light c
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
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