Plz could you check this working for me?? 1. The problem statement, all variables and given/known data Two blocks, A and B (with mass 50 kg and 100 kg, respectively), are connected by a string, as shown in figure. The pulley is frictionless and of negligible mass. The coefficient of kinetic friction between block A and the incline is μk = 0.25. Determine the change in the kinetic energy of block A as it moves from (C) to (D), a distance of 20 m up the incline (and block B drops down a distance of 20 m) if the system starts from rest. 2. Relevant equations Block A T-μR+mg sinθ= ma Block B mg-T=ma 3. The attempt at a solution acceleration in both blocks is the same since they are connected directly with no elastic strings Block A T=ma+μR-mg sinθ Block B T=mg-ma Substitute for T mg-ma=ma+μR-mg sinθ (100 x 9.8) - (100a) = (50a) + (0.25 x 50 x 9.8 x cos 37) - (50 x 9.8 x sin 37) 980-100a-50a=97.83-294.89 -100a-50a=97.83-294.89-980 -150a=-1177.057 a=7.8 is this correct????