Electric Field Halfway Between Two Charges

AI Thread Summary
To find the electric field at the halfway point between two charges, one must calculate the electric fields produced by each charge separately and then sum them. The charges are located at specific coordinates, with one being negative and the other positive. The distance used in calculations should be accurate, as it directly affects the electric field values. Clarification on the calculations is necessary to identify any errors made in the process. Accurate calculations and clear communication of steps are essential for resolving the problem.
Xet
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Homework Statement


q1 (-6.5E-7 C) @ 6 cm to the right of origin (X,Y coordinate is 6,0)
q2 (6.5E-7 C) @ 21 cm to the left of origin (X,Y coordinate is -21,0)

At the half-way point of these two charges, what is the E field value...?

Homework Equations


sum of electric fields
electric field at point is equal to constant times the charge, all divided by radius squared
constant is 8.99E9 Nmm/(CC)

The Attempt at a Solution


I found the two E's from the point to the half-way mark...I'm suppose to add the two E's because it's going from negative to positive...right? Well...I got it wrong...
 
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Xet said:

Homework Statement


q1 (-6.5E-7 C) @ 6 cm to the right of origin (X,Y coordinate is 6,0)
q2 (6.5E-7 C) @ 21 cm to the left of origin (X,Y coordinate is -21,0)

At the half-way point of these two charges, what is the E field value...?

Homework Equations


sum of electric fields
electric field at point is equal to constant times the charge, all divided by radius squared
constant is 8.99E9 Nmm/(CC)


The Attempt at a Solution


I found the two E's from the point to the half-way mark...I'm suppose to add the two E's because it's going from negative to positive...right? Well...I got it wrong...


What did you use for the distance when you calculated the E field?
 
kdv said:
What did you use for the distance when you calculated the E field?

Rather dumb question to ask...but I used .135 m as R.
 
Xet said:
Rather dumb question to ask...but I used .135 m as R.

It is not a dumb question at all. You didn't show your work. How can we tell you what you did wrong if you don't show any calculations?
 
Xet said:
Rather dumb question to ask...but I used .135 m as R.

well, if it's a dumb question to ask I won't ask any question anymore.

Best luck
 

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