Pointwise convergence of integral of Fourier series

twizzy
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Homework Statement


If f(x) is a piecewise-continuous function in [-L,L], show that its indefinite integral F(x) = \int_{-L}^x f(s) ds has a full Fourier series that converges pointwise.

Homework Equations


Full Fourier series: f(x)=\frac{1}{2}A_0 + \sum_{n=1}^\infty A_n \cos (\frac{n \pi }{L}x) + B_n \sin (\frac{n \pi}{L}x)

Definition: \sum_{n=1}^\infty f_n (x) converges to f(x) pointwise in (a,b) if for each a<x<b we have
\Big| f(x) - \displaystyle{\sum_{n=1}^\infty f_n (x)} \Big| \to 0 as N\to\infty.

The Attempt at a Solution


I think I need to somehow justify integrating term-by-term, but am not sure how to proceed. Any ideas?
 
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If you want to integrate term by term, you need uniform convergence.
Haven't really looked at this, so not saying that term by term integration is the solution here.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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