1. The problem statement, all variables and given/known data Find the area of the region between the inner and outer loop of the limicon r=2cos(x)-1 2. Relevant equations A=(2(1/2)small circle)-(2(1/2)large circle) 3. The attempt at a solution I don't even know where to start with this question because I can't figure out the formula for the inner circle to plug into the Area formula. The hint I have received from the teacher is "Use symmetry: the area of the shaded region is twice the area in half of the little loop subtracted from twice the area in half of the big loop. The integration is much neater if you choose a good way to compute those two half areas." I have included the teachers hint into the equation above to try and help my understand what he's looking for but I'm still scratching my head. Any help would be greatly appreciated and thanks in advance!