1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Polar bonds

  1. Jan 1, 2009 #1
    Hello!
    Quick question, but it's really bugging me!
    Exergonic reactions often yield polar molecules as the products (e.g. combustion of methane). Are these polar molecules 'favourable' because the electrons are spending more time in a lower energy region; or is this wrong, and there's a different reason why polar molecules are more stable?
    All responses appreciated.
     
  2. jcsd
  3. Jan 2, 2009 #2

    chemisttree

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member

    Give us an example of the polar molecules you are referring to regarding the combustion of methane. CO2 and H2O? One is polar and one isn't...
     
  4. Jan 2, 2009 #3
    Ohhhh, CO2 isn't polar because the 'pull' of the oxygen atoms is 'balanced'. So I'm guessing polar molecules are not stable more generally? Why would they be, I suppose...
    In that case, is there a method of determining the most likely products of a reaction, given that they attempt to form the most stable products?
    Thanks for the reply, and any further ones. :smile:
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Polar bonds
  1. Polar bonds (Replies: 10)

  2. Bonds: Polar Covalent (Replies: 4)

Loading...