Polynomial transformation of random variable

raynard
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Homework Statement



Given a random variable X with a known distribution (e.g. a beta distribution), find the distribution of
f(X) = X^2 + X

The Attempt at a Solution



I've tried the normal approaches: the standard transformation theorem; conditioning on X; Laplace transformation, etc. They don't seem to work. Any hints?
 
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Thanks for the reply!

I tried the standard method you described, but I see no easy way to find the inverse of

f: x -> x^2 + x
 
Yup, I don't think it's very pretty...
I have to say, I'm pretty rusty when it comes to probability. I remember the best ways to solve this type of questions is to write Y = X2 + X, and then:
P(Y < y) = P (X2 + X < y) = P(X2 + X - y < 0 ) = ...

Then you'd have to solve this inequality and proceed from there...
But maybe there are shortcuts. I just responded cause I saw no one else did :-)
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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