Potential at a point in a circuit

  • Thread starter vadevalor
  • Start date
  • #1
vadevalor
35
0
ImageUploadedByTapatalk1379582898.613208.jpg


Why is the potential at X , denoted by V, not

V/8 = 4.8/(4.8+7.6) ? Why is numerator of resistance part 7.6 and not 4.8 by potential divider principle?
 

Answers and Replies

  • #2
tiny-tim
Science Advisor
Homework Helper
25,836
255
hi vadevalor! :smile:

conventionally, the current flows from the positive terminal (long line) to the negative terminal (short line)

(the electrons, of course go the other way, towards the positive!)

so the short line is at zero potential, and you have to start from the short line to get to X to find the potential at X, ie the potential difference from zero

(see eg "Electric Potential Diagrams" at http://www.physicsclassroom.com/class/circuits/u9l1c.cfm)

ie you go through the 7.6Ω, so 7.6 is in the numerator :wink:
 
  • #3
grzz
998
15
The values 4.8V and 1.6V shown on the circuit diagram are misleading. Should not the unit be Ω instead of V?

The equivalent circuit is a voltage supply of 8V connected to 4.8Ω in series with 7.6Ω as shown correctly in your diagram.

Hence 8V is the voltage on (4.8 + 7.6)Ω.

And the voltage on 4.8Ω can be found be using direct proportion.
 
  • #4
vadevalor
35
0
Thank you all for your inputs! I realised its the direction after thinking for so long. And yea it should be ohm instead of v.

I have another question regarding potential could you guys help me? Answer is A but i dont understand the solution as there are 'conflicting battery direction' and i dont know how to start

ImageUploadedByTapatalk1379591023.772679.jpg


Thanks!!
- curious lost soul
 
  • #5
tiny-tim
Science Advisor
Homework Helper
25,836
255
hi vadevalor! :smile:
Answer is A but i dont understand the solution as there are 'conflicting battery direction' and i dont know how to start

start by replacing the three batteries by one 3V battery …

what is the potential at Y? and where is that measured from?

and now adjust that to start from X instead :wink:
 
  • #6
vadevalor
35
0
hi vadevalor! :smile:


start by replacing the three batteries by one 3V battery …

what is the potential at Y? and where is that measured from?

and now adjust that to start from X instead :wink:

Should i put the 3v battery to the right or left of X and should i go from + terminal to -terminal from X to Y like current flow or electron flow?

Smiles :D
 
  • #7
tiny-tim
Science Advisor
Homework Helper
25,836
255
hi vadevalor! :smile:
Should i put the 3v battery to the right or left of X and should i go from + terminal to -terminal from X to Y like current flow or electron flow?

Smiles :D

you must always always ALWAYS use current flow not electron flow!

X is somewhere in the middle of the 3V battery, isn't it? :wink:
 
  • #8
vadevalor
35
0
hi vadevalor! :smile:


you must always always ALWAYS use current flow not electron flow!

X is somewhere in the middle of the 3V battery, isn't it? :wink:

ImageUploadedByTapatalk1379593167.784346.jpg


Think i got it! Yes! So its 2-1.5= 0.5v following current direction. But when do i know to use current or electron flow direction? Above for potential divider i was told to look at electron flow
 
  • #9
tiny-tim
Science Advisor
Homework Helper
25,836
255
yes, i like your diagram …

you've split the batteries into two: a 2V and a 2 minus 1 = 1V battery going the same way,

so it's easy to see whether to add or subtract :smile:
Above for potential divider i was told to look at electron flow

i don't understand that :redface:

it's always current flow​

what exactly did they say? :confused:
 
  • #10
vadevalor
35
0
hi vadevalor! :smile:

conventionally, the current flows from the positive terminal (long line) to the negative terminal (short line)

(the electrons, of course go the other way, towards the positive!)

so the short line is at zero potential, and you have to start from the short line to get to X to find the potential at X, ie the potential difference from zero

(see eg "Electric Potential Diagrams" at http://www.physicsclassroom.com/class/circuits/u9l1c.cfm)

ie you go through the 7.6Ω, so 7.6 is in the numerator :wink:

Its the third paragraph from your first answer :) starting from the short line (electron flow direction)
 
  • #11
tiny-tim
Science Advisor
Homework Helper
25,836
255
Its the third paragraph from your first answer :) starting from the short line (electron flow direction)

ah, i see, you're interpreting the flow direction as the direction for measuring the potential

no, the flow direction (= the current direction) is the direction the charge is moving (which we assume is a positive charge, so the opposite of the electron flow direction)

since the charge moves from high to low potential, the potential decreases as the charge moves, so the potential difference is measured in the opposite direction:

ie we use a positive charge (ie not an electron), and so it will flow outside the battery from the long line (+ve) to the short line (-ve), and the potential will be highest at the long line, and decrease to zero at the short line :wink:
 

Suggested for: Potential at a point in a circuit

  • Last Post
Replies
14
Views
1K
Replies
1
Views
1K
Replies
3
Views
9K
Replies
2
Views
229
Replies
9
Views
812
Replies
5
Views
2K
  • Last Post
Replies
2
Views
1K
Replies
2
Views
3K
  • Last Post
Replies
2
Views
354
Replies
7
Views
9K
Top