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dark_angeL23
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Homework Statement
A small electrically charged object is suspended by a thread between the vertical plates of a parallel-plate capacitor. The acceleration of gravity is 9.8 m/s^2.
What is the potential difference between the plates? Answer in units of kV.
Given: tetha = 14 degrees
mass of the object = 152 mg
q = 15 nC
distance between the two plates = 5.6 cm
Homework Equations
I used the following:
delta V = U/Q
U = F x d
The Attempt at a Solution
I got U = 0.0000834176 Joules
and I got V = 5561.1733333 V
which is V = 5.561173333 kV
but it's wrong.
could someone please please tell me how to do it?