Potential Difference in and Electron/de Broglie Equation

AI Thread Summary
To determine the potential difference required to accelerate an electron from rest to achieve a de Broglie wavelength of 0.1 nm, the relevant equations include E = hf and E = hλ/c. Initial calculations yielded an incorrect energy value of 2.21e-58 J, prompting a re-evaluation. After correcting the calculations, the required voltage difference was found to be 150V. This process highlights the importance of accurate calculations and unit conversions in solving physics problems.
wilywilly0
Messages
2
Reaction score
0

Homework Statement



Through what potential difference should you accelerate an electron from rest, such that it's de Broglie wavelength will be 0.1 nm.

Homework Equations



E = hf
λf = c

The Attempt at a Solution



My Thinking was;

E = hf
E = hλ/c
E= 6.626e-34 * 1e-10/3e8

which turned out 2.21e-58 J, which I'm pretty sure is wrong.

Anyone with some ideas or a worked solution would be fantastic :D

Regards all,

Will.
 
Physics news on Phys.org
You're right so far, though you should re-check your final calculation, since you're off by a couple orders of 10. So now you need to figure out what voltage difference is going to supply the energy you calculated. I would recommend converting the energy you calculate into electron volts, since those will make the voltage calculation easier.
 
Solved, 150V, thanks jd :)

Will.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top