Potential difference in uniform electric field

AI Thread Summary
A uniform electric field of 325 V/m is directed in the negative y direction, and the coordinates for points A and B are provided. To calculate the potential difference V(B)-V(A), the y-component of the distance between the points (0.8 m) is used, leading to the equation V(B)-V(A) = + E x distance. The initial calculation resulted in 260 V, but there is a caution regarding the sign due to the direction of the electric field. The method is generally correct, emphasizing the importance of considering the electric field's direction and the corresponding distance component.
lha08
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Homework Statement


A uniform electric field of magnitude 325 V/m is directed in the negative y direction. The coordinates of point A are (-0.200, -0.300) m and those of point B are (0.400, 0.500) m. Calculate the potential difference V(B)-V(A).


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The Attempt at a Solution


What I first did was that since the electric field is pointing towards the negative y direction, I think that I should use only the y component of the distance between Point A and B (0.8 m) and then use V(B)-V(A)= + E X distance. This gave me 260 V...I'm not sure but can anyone tell me if I'm doing it wrong and making a mistake somewhere?
 
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lha08 said:
What I first did was that since the electric field is pointing towards the negative y direction, I think that I should use only the y component of the distance between Point A and B (0.8 m) and then use V(B)-V(A)= + E X distance. This gave me 260 V...I'm not sure but can anyone tell me if I'm doing it wrong and making a mistake somewhere?

Hi lha08! :smile:

Method looks ok …

electric potential = potential energy per charge,

and potential energy is just another name for (minus) the work done, which is force "dot" distance, or E.d.

E is in the y-direction, so E.d only uses the y-coordinate of distance (and be careful about the sign :wink:)
 
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