Calculating Potential Difference in a Uniform Electric Field | Example Problem

AI Thread Summary
The discussion focuses on calculating the potential difference between two points in a uniform electric field defined by E = (20000i - 50000j) V/m. The user attempts to apply the formula ΔV = -E·Δs, where Δs is the distance between the points, calculated as √(9cm)² + (1cm)². The user arrives at a potential difference of -4876.5 V but questions whether the angle of the electric field should be considered, suggesting the need for a dot product approach. The conversation highlights the importance of incorporating vector components in the calculation of potential difference in electric fields. Properly accounting for directionality in the electric field is crucial for accurate results.
KillerZ
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I am wondering if I did this right.

Homework Statement



What is the potential difference between the points (x_i, y_i) = (0cm, -5cm) and (x_f, y_f) = (1cm, 4cm) in a uniform electric field equal to E = (20000i - 50000j) V/m ?

Homework Equations



\Delta V = V(s_{f})-V(s_{i}) = -\int^{s_{f}}_{s_{i}}E_{s}ds

E is uniform therefore:

\Delta V = - E_{s}\Delta s

\Delta s = \sqrt{(9cm)^{2}+(1cm)^{2}}

= \frac{\sqrt{82}}{100} m

E = \sqrt{(20000V/m)^{2}+(-50000V/m)^{2}}

= \sqrt{2.9*10^{9}} V/m

The Attempt at a Solution



\Delta V = - E_{s}\Delta s

= -(\sqrt{2.9*10^{9}} V/m)(\frac{\sqrt{82}}{100} m)

= -4876.5 V
 
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Don't you have to take the angle into account? Only a component of E is in the direction of the distance.
 
I think you take your

ΔV = E*Δs a little differently. Namely as the dot product of the E vector and the s vector, such that

ΔV = Ex*Δx i + Ey*Δy j
 
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