Potential Energy vs x phase diagram

Blakely42
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Homework Statement
Consider a mass m confined to the x axis and subject to a force F = kx where k > 0. Write down and sketch the potential energy U(x) and describe the possible motions of the mass. (Distinguish between the cases that E > 0 and E < 0.
Relevant Equations
E = T + U
L = T - U
F = -Grad(U)
H(p,x) = T + U
U(x) = - ∫Fdx = - (1/2)kx^2. T = (1/2)m(x')^2. E = (1/2)[m(x')^2 - kx^2]. We could write out the Lagrangian here, but the chapter this comes from (Taylor's Classical Mechanics 13.6) indicates we should probably write the Hamiltonian, H = T + U.

As far as I can tell, this doesn't tell me a single thing about what happens when E < 0 or E > 0. Even chapter 13 only deals with phase diagrams of x vs p. How am I supposed to translate this idea to an x vs U(x) diagram? I don't think there's enough information to do that here.Update: My professor answered my email, saying to think of it like a central force problem, but central force problems have energy from their rotational momentum; we use that energy in calculating U_eff(x). I don't see how we can do that here. It's not just an issue of getting the correct answer. I'm trying to understand how the equations yielded by the Hamiltonian actually tell me the behavior. i.e. how do the equations translate to English?
 
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Are you saying you don't know how to sketch U(x) vs. x?
 
yes
 
What's stopping you? This is something you should have learned how to do in high school algebra. If you really have no idea of how to plot this function, you may want to reconsider whether you're properly prepared for this mechanics course.
 
Why use the energy to reply to a thread, but not the energy to answer a question? Thanks for the homework "help".
 

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Because what you're asking is like a calculus student asking how to calculate 2+2. It's very surprising that any student in an upper-division mechanics class doesn't know how to sketch a function of a single variable. It's surprising enough to where I suspect that's not your real question, which is why I'm asking you to dig a little deeper to identify exactly where you're getting stuck.
 
The potential energy is simply a parabola facing downwards, I don’t see where you’re having difficulty.
 
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