Potential Function from a simple conservative force

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SUMMARY

The discussion focuses on finding potential functions for two conservative forces: F1 = xi + yj and F2 = yi + xj. The correct potential function for F1 is derived through integration, resulting in V1 = -xy + C, while the initial attempt for F2 incorrectly yielded -2xy + C. The correct approach involves integrating the force components along specified paths, confirming that both forces are conservative and that the work done is path-independent.

PREREQUISITES
  • Understanding of vector calculus and conservative forces
  • Familiarity with potential energy concepts in physics
  • Knowledge of partial derivatives and integration techniques
  • Experience with line integrals in multivariable calculus
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  • Study the method of integrating vector fields to find potential functions
  • Learn about line integrals and their applications in physics
  • Explore the properties of conservative forces and their implications
  • Investigate the relationship between force fields and potential energy in different coordinate systems
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Students and professionals in physics, particularly those studying mechanics and vector calculus, as well as educators teaching concepts related to conservative forces and potential energy.

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Homework Statement


Find the potential functions for these conservative forces:

(1)F=xi+yj

(2)F=yi+xj

Homework Equations


F=-[tex]\nabla[/tex]V (Force = -del (Pot.energy))


The Attempt at a Solution



So, I'm guessing to get V I just need to integrate F. For the first equation that gets me the right answer hurray!

However I think my method is wrong(or my general understanding the opposite of partial derivatives). Doing the same thing to eqn 2 leaves me with a slight problem.
-([tex]\int[/tex]y dx +[tex]\int[/tex]x dy)leaves me with -2xy+C. The correct answer should be -xy+C

(I checked and it is indeed a conservative force)

Please enlighten me
Thanks in advance
 
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For a conservative force, the work between two points is independent on the connecting path. Start to integrate from point (0,0) to point P(X,Y).
You can follow the line along the x-axis from x=0 to x=X and then a straigth line parallel to the y-axis from (X,0) to (X,Y). The work done is

[tex]V(0,0)-V(X,Y)=\int_{(0,0)}^{(X,Y)}{ydx+xdy}=\int_{(0,0)}^{(0,X)}{ydx}+\int_{(X,0)}^{(X,Y)}{xdy}[/tex]

As y=0 along the first line, and x=X along the second one, the first integral is 0, the second one is XY.

ehild
 
solved. thanks
 

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