Potential vs Charge Homework: Find the Answers!

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Two conducting spheres, one charged and the other neutral, reach charge equilibrium when connected by a wire. The charge distribution depends on their radii, with the smaller sphere holding less charge than the larger one to maintain equal potential. The conservation of charge and the requirement for equal potential lead to the conclusion that the charges will not be distributed equally. The mathematical relationship shows that potential (V) is inversely related to radius (r), meaning smaller spheres require a smaller charge to achieve the same potential. Understanding these principles clarifies why the charge distribution is not equal despite the initial assumption.
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Homework Statement


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Two conducting spheres are far apart. The smaller sphere carries a total charge Q. The larger sphere has a radius that is twice that of the smaller and is neutral. After the two spheres are connected by a conducting wire, the charges on the smaller and larger spheres, respectively, are:
A. Q/2 and Q/2
B. Q/3 and 2Q/3
C. 2Q/3 and Q/3
D. zero and Q
E. 2Q and −Q

The Attempt at a Solution


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I thought that charge would spread equally by the two spheres, but it seems that it deppends on the radius of them. Can someone tell me why? mathematically if possible. Also, why does the potential does NOT deppend on the radius? since we have V = Qk/r

ty vm :)
 
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Well, potential depends on the radius you just wrote V= kQ/ r

r...r...r...
Thats the radius

The conditions are:

Conservation of charge and same potential on both spheres after the connection because when spheres reach the potential equilibrium there's no more flow of charges

I suggest setting a system of equation with variables the final charges on each spheres
 
So what you're telling me is that when the two spheres are connected there is a flow of charge (which would be described as a function) that tends to zero as the system reaches a potential equilibrium?
 
Fips said:
So what you're telling is that when the two spheres are connected there is a flow of charge (which would be described as a function) that tends to zero as the system reaches a potential equilimbrium?

Well, you can see it like that, but i would prefer to think it using physics, like you know charges of same sign tends to repell each other, on a sphere they tend to get as far as they can till they reach equilibrium, if you connect a charged sphere to a neutral one you are actually giving the charges more space to move and make distance between each other till they reach equilibrium...

About you first question on why charges tends to be distributed not equally, you can see it also matematically:
V has to be the same at equilibrium right? If on a sphere radius is smaller to maintain the same V as the sphere with greater radius it has to change Q by smalling it, so the little sphere will also have less charges
 
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waaa thanks that last response was very enlightening ^^ thank you!
 
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